Write a C program to find 1+1/2+1/3+1/4+....+1/n

Program to sum of series 1+1/2+1/3+1/4+....+1/n

In this program, if inverse of a sequence follow rule A.P i.e , Arithmetic progression, then it is said to be in harmonic progression can be denoted: 
1/a, 1/(a + d), 1/(a + 2d), 1/(a + 3d)........ , 1/(a + nd).

As Nth term of AP is given as ( a + (n-1)d ). Hence, Nth term of harmonic progression is reciprocal of Nth term of AP, which is: 1/(a + (n-1)d)

Where 'a' is the 1st term of AP and 'd' is the common difference. We can use a for loop to find sum.

  •  Program:

#include<stdio.h>
#include<conio.h>

int main()
{
int n,i,j,fact=1;
float sum=0;
printf("\n Enter Value of n : ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
    fact=1;
    for(j=i;j>0;j--)
    {
        fact=fact * j;
     }
    sum=sum+(1.0/fact);
}
printf("\n Sum of Series = %f",sum);
return 0;
}


  •  Output:

Enter Value of n : 6
Sum of Series = 1.718055

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