Write a C program to print following 1-2-3 patterns

1-2-3 patterns

I)    
        1
        12
        123
        1234
        12345
       
  •  Program:

#include<stdio.h>
#include<conio.h>

int main()
{
    int a,b,c;

    printf("Enter the number: ");
    scanf("%d",&c);

    for(a=1;a<=c;a++)
    {
        for(b=1;b<=a;b++)
        {
            printf("%d",b);
        }
        printf("\n");
    }
    return 0;
}

  •  Output:
Enter the number: 5
1
12
123
1234
12345


II)
        12345
        1234
        123
        12
        1

  •  Program:

#include<stdio.h>
#include<conio.h>

int main()
{
    int a,b,c;

    printf("Enter the number: ");
    scanf("%d",&c);

    for(a=c;a>=1;a--)
    {
        for(b=1;b<=a;b++)
        {
            printf("%d",b);
        }
        printf("\n");
    }
    return 0;
}

  •  Output:

Enter the number: 5 12345 1234 123 12 1

III)
        1
        22
        333
        4444
        55555
        666666

  •  Program:

#include<stdio.h>
//here we have not used conio.h bcz in this code one status will return the value.

int main()
{
    int a, b, c;

    printf("Enter the number: ");
    scanf("%d",&c);

    for(a=1;a<=c;a++)
    {
        for(b=1;b<=a;b++)
        {
            printf("%d",a);
        }
        printf("\n");
    }
    return 0;
}

  •  Output:

Enter the number: 6 1 22 333 4444 55555 666666

IV)
        666666
        55555
        4444
        333
        22
        1

  •  Program:

#include<stdio.h>
//here we have not used conio.h bcz in this code one status will return the value.

int main()
{
    int a, b, c;

    printf("Enter the number: ");
    scanf("%d",&c);

    for(a=c;a>=1;a--)
    {
        for(b=1;b<=a;b++)
        {
            printf("%d",a);
        }
        printf("\n");
    }
    return 0;
}

  •  Output:

Enter the number: 6 666666 55555 4444 333 22 1
 
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