Write a C program to print following 1-2-3 patterns
1-2-3 patterns
I)
1
12
123
1234
12345
- Program:
#include<stdio.h>#include<conio.h>int main(){int a,b,c;printf("Enter the number: ");scanf("%d",&c);for(a=1;a<=c;a++){for(b=1;b<=a;b++){printf("%d",b);}printf("\n");}return 0;}
- Output:
Enter the number: 5112123123412345
II)
12345
1234
123
12
1
- Program:
#include<stdio.h>#include<conio.h>int main(){int a,b,c;printf("Enter the number: ");scanf("%d",&c);for(a=c;a>=1;a--){for(b=1;b<=a;b++){printf("%d",b);}printf("\n");}return 0;}
- Output:
Enter the number: 5 12345 1234 123 12 1
III)
1
22
333
4444
55555
666666
- Program:
#include<stdio.h>//here we have not used conio.h bcz in this code one status will return the value.int main(){int a, b, c;printf("Enter the number: ");scanf("%d",&c);for(a=1;a<=c;a++){for(b=1;b<=a;b++){printf("%d",a);}printf("\n");}return 0;}
- Output:
Enter the number: 6 1 22 333 4444 55555 666666
IV)
666666
55555
4444
333
22
1
- Program:
#include<stdio.h>//here we have not used conio.h bcz in this code one status will return the value.int main(){int a, b, c;printf("Enter the number: ");scanf("%d",&c);for(a=c;a>=1;a--){for(b=1;b<=a;b++){printf("%d",a);}printf("\n");}return 0;}
- Output:
Enter the number: 6 666666 55555 4444 333 22 1
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